Abstract
An exact boson mapping of the deformed mean-field plus equal strength pairing Hamiltonian is considered. In the mapping, fermion pair operators are mapped exactly to the corresponding bosons. The mapping occurs at the level of the Richardson–Gaudin equations. The image of the mapping results is a Bose–Hubbard model with level-dependent hopping. Although the resultant Bose–Hubbard Hamiltonian is non-Hermitian, a part of spectrum of the Bose–Hubbard Hamiltonian with U/t = 1 determined by the corresponding Richardson–Gaudin (Bethe ansatz) equations corresponds exactly to the whole spectrum of the pairing Hamiltonian.
Talk to us
Join us for a 30 min session where you can share your feedback and ask us any queries you have
More From: Journal of Physics G: Nuclear and Particle Physics
Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.