Abstract
In the title compound, C21H19N3O5, the phthalimide and benzamidazole ring systems are linked by a propyl chain. The benzamidazole unit also carries an ethoxycarbonyl substituent. The phthalimido and benzimidazole ring systems are essentially planar, the maximum deviations from their mean planes being 0.008 (2) and 0.020 (2) Å, respectively. The two ring systems are almost orthogonal to one another, making a dihedral angle of 82.37 (8)°. In the crystal, C—H⋯O hydrogen bonds and C—H⋯π contacts stack the molecules along the b axis.
Highlights
C21H19N3O5, the phthalimide and benzamidazole ring systems are linked by a propyl chain
As a continuation of our research into the development of substituted benzimidazol-2-one derivatives (Belaziz et al, 2013) we report here the synthesis of a new benzimidazol-2-one derivative by the reaction of N-(3-bromopropyl)phthalimide with 1-ethoxycarbonyl-benzo[d]imidazol-2(3H)-one using the same conditions to produce the title compound (Scheme 1)
Symmetry codes: (i) x+1, y, z; (ii) −x−1, −y+1, −z+1; (iii) −x+1, −y+1, −z; (iv) −x, −y, −z
Summary
Crystal data a Laboratoire de Chimie Organique Appliquée, Université Sidi Mohamed Ben.
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