Abstract

The enthalpy increments of the compounds Ba 2Te 3O 8(s) and Ba 3Te 2O 9(s) were measured in the temperature range 298–965 K, using a high temperature Calvet calorimeter. The values were least square fitted in the following temperature dependent polynomial equations: Δ H 298.15 K T ( J/mol ) B a 2 T e 3 O 8 ( s ) = − 77 , 233 + 234.87 T + 0.08108 T 2 ( 298.15 – 862.8 K ) , Δ H 298.15 K T ( J/mol ) B a 2 T e 3 O 8 ( s ) = 21 , 533 − 209.39 T + 0.46007 T 2 ( 862.8 – 965 K ) , Δ H 298.15 K T ( J/mol ) B a 3 T e 2 O 9 ( s ) = − 116 , 177 + 338.96 T + 0.00741 T 2 + 4 , 310 , 572 T . The temperature differentials of the above equations gave the heat capacity equations for the respective compounds, which were compared with Neumann–Kopp's estimated heat capacities. As heat capacity of TeO 3 was not available in literature, it was estimated from that of TeO 2. Using the Gibbs energy of formation data of Ba 3Te 2O 9(s), reported in literature, Δ f H 298.15 K ° , and S 298.15 K ° of the compound were calculated as −2258 kJ/mol and 822 J/(mol K), respectively.

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