Abstract

We prove the three embeddedness results as follows. (i) Let $\Gamma_{2m+1}$ be a piecewise geodesic Jordan curve with $2m+1$ vertices in $\mathbb{R}^n$, where $m$ is an integer $\geq2$. Then the total curvature of $\Gamma_{2m+1}\lt 2m\pi$. In particular, the total curvature of $\Gamma_5\lt 4\pi$ and thus any minimal surface $\Sigma \subset \mathbb{R}^n$ bounded by $\Gamma_5$ is embedded. Let $\Gamma_5$ be a piecewise geodesic Jordan curve with $5$ vertices in $\mathbb{H}^n$. Then any minimal surface $\Sigma \subset \mathbb{H}^n$ bounded by $\Gamma_5$ is embedded. If $\Gamma_5$ is in a geodesic ball of radius $\frac{\pi}{4}$ in $\mathbb{S}^n_+$, then $\Sigma \subset \mathbb{S}^n_+$ is also embedded. As a consequence, $\Gamma_5$ is an unknot in $\mathbb{R}^3$, $\mathbb{H}^3$, and $\mathbb{S}^3_+$. (ii) Let $\Sigma$ be an $m$-dimensional proper minimal submanifold in $\mathbb{H}^n$ with the ideal boundary $\partial_{\infty} \Sigma = \Gamma$ in the infinite sphere $\mathbb{S}^{n-1}=\partial_\infty \mathbb{H}^n$. If the Möbius volume of $\Gamma$ $\widetilde{\rm Vol}(\Gamma) \lt 2{\rm Vol}(\mathbb{S}^{m-1})$, then $\Sigma$ is embedded. If $\widetilde{\rm Vol}(\Gamma) = 2{\rm Vol}(\mathbb{S}^{m-1})$, then $\Sigma$ is embedded unless it is a cone. (iii) Let $\Sigma$ be a proper minimal surface in $\mathbb{H}^2 \times \mathbb{R}$. If $\Sigma$ is vertically regular at infinity and has two ends, then $\Sigma$ is embedded.

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