Abstract
In the title compound, C14H11ClN2O4·CH3OH, the molecule adopts an E conformation about the C=N bond. The compound is in the enamine–keto form. The two terminal benzene rings make a dihedral angle of 10.53 (9)°. Intra-molecular O—H⋯O and O—H⋯N hydrogen bonding stabilizes the molecular structure. In the crystal, O—H⋯O hydrogen bonds link the molecules, forming chains running along the b axis.
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