Abstract
A combination of experiment and theory indicate that when Me 3O + undergoes vertical Franck–Condon one-electron reduction, it does not produce a stable Me 3O species, but decomposes to give MeOMe and Me . Theoretical calculations at the CCSD(T)/aug-cc-pVDZ//B3LYP/6-311G(d) level of theory indicate that the symmetrical radical Me 3O is not a stable species. However, there is a stable doublet neutral corresponding to a van der Waals complex MeOMe⋯Me, a species which requires only 4.5 kJ mol −1 of excess energy to cause decomposition to MeOMe and Me .
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