Abstract
Nd 2Fe 14B exhibits a spin reorientation from an axial arrangement to what appears to be a conical one as the temperature is lowered below ≈ K. In contrast, Pr 2Fe 14B remains axial down to 4.2 K. It is shown that this behavior can be interpreted using a crystal field Hamiltonian of the form ▪ = B 0 2O 0 2 + B 0 4O 0 4 + 2(g j−1)μ BJ →·H → Using values of CFOAS (Crystal Field Overall Splitting) and ‖H exch‖ typical of Nd 3+ and Pr 3+ in related intermetallic compounds, this Hamiltonian predicts that Pr 3+ will possess uniaxial anisotropy in its ground state, while Nd 3+ exhibits an easy cone.
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