Abstract
A simple method was developed for determining lupeol in fruits by reverse-phase high performance liquid chromatography(RP-HPLC).Separation was carried out on reversed-phase Nucleosil C18 column(5μm,250 mm × 4.6 mm i.d.) by using a mixture of methanol and water(20:80,pH 3.2 ± 0.05 adjusted by 50% phosphoric acid) as mobile phase A,and methanol containing 0.01% phosphoric acid as mobile phase B(A:B = 4:96) at a flow rate of 1.2 mL/min.The column temperature was hold at 40 ℃,and the detection wavelength was set as 210 nm.The correlation coefficient of the linear calibration curve(y = 4.6068x + 11.2640) was 0.9992 at the concentration range of 5 to 250μg/mL.The relative standard deviations(RSDs) of retention time and peak area in precision experiments for 5 replicate analyses and 9 replicate analyses in 48 h were 0.2107% and 1.2843%,and 0.3383% and 1.9737%,respectively.The recovery rate range was between 94.971% and 101.964% with a RSD of 2.5825%.The detection limit of this method was 1.8886μg/mL.The content of lupeol in dried Chinese olive powder was 359 μg/g,which was higher than that in strawberry,banana,Jufeng grape,American red grape and papaya.Therefore,the developed method is practicable for qualitative and quantitative determination of lupeol in fruits.
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