Abstract

Detailed chemical kinetics simulations of the cooling of hydrocarbon combustion products show that the mole fraction of CO freezes well above equilibrium levels at a value that depends on the cooling rate. The frozen mole fraction of CO can be expressed as a function of the system pressure and the mole fractions of CO 2, O 2, and H 2O X CO, f = 2.0 × 10 −9[ X CO 2 /( X O 2 X H 2O )]( Pτ) −1.6where τ is the temperature relaxation time, inversely proportional to the cooling rate. The ratio of mole fractions in this result can also be derived by partial equilibrium analysis. However, this derivation yields X CO, f proportional to X OH 2 rather than ( Pτ) −1.6. The dependence on cooling rate is shown to be a kinetic effect due to the relatively slow forward rate of the principal CO oxidation reaction. This rate is proportional to PX OH, and X CO freezes when X OH is too small to maintain the consumption rate for CO that is needed to keep X CO near equilibrium at a given cooling rate. Partial equilibrium analysis shows that X OH, f , the value of X OH when X CO freezes, is proportional to ( Pτ) −1. The temperature, T f where X OH equals X OH, f is found by setting X OH, f = X OH,0 exp(−γ OH/ T f ), where γ OH is a fitting parameter related to equilibrium constants. Using T f and the equilibrium value of γ OH with the temperature-dependent result of the partial equilibrium analysis gives X CO proportional to ( Pτ) −1.56. This gives values of frozen X CO in reasonable agreement with the detailed chemical kinetics results. At high cooling rates, γ OH is a function of τ that can be found by a curve fit to X OH vs. T data from detailed kinetics calculations. Using this function to calculate T f improves the agreement with the detailed chemical kinetics results.

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