Abstract
In Chapter 5 we saw that the law of quadratic reciprocity provided the answer to the question. For which primes p is the congruence x2≡ a (p) solvable ? Here a is a fixed integer. If the same question is considered for congruences xn≡ a (p), n a fixed positive integer, we are led into the realm of the higher reciprocity laws. When n = 3 and 4 we speak of cubic and biquadratic reciprocity.
Talk to us
Join us for a 30 min session where you can share your feedback and ask us any queries you have