Abstract

AbstractN2H6(Sb2F11)2 was synthesized by the reaction of N2H6F2 with excess of SbF5 in anhydrous hydrogen fluoride (aHF). It crystallizes in the triclinic space group P$\bar{1}$ (No. 2) with a = 6.6467(3) Å, b = 8.3039(4) Å, c = 8.3600(5) Å, α = 76.394(5) o, β = 70.161(5) o, γ = 70.797(5) o, V = 405.90(4) Å3 at 150 K, Z = 2. When it is redissolved in aHF, it solvolysis with the release of SbF5 yielding N2H6(SbF6)2 which crystallizes in the monoclinic C2/c space group (No. 15) with a = 7.3805(3) Å, b = 12.3248(5) Å, c = 10.4992(4) Å, β = 92.218(4) o, V = 954.33(7) Å3 at 150 K, and Z = 8. No other phases were observed in crystallization products when different molar ratios of N2H6F2/SbF5 (1:1,2:3,1:3) in aHF were used as starting materials.

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