Abstract
The crystal structure of the compound formed by the neptunyl(V) ion ( 237NpO 2 + ) and mellitic acid was determined. The stoichiometric formula of the compound was Na 4(NpO 2) 2C 12O 12·8H 2O with the following crystal data: Z = 4; V c = 2486.7 A ̊ 3 ; D calc = 2.96 g cm −3; a = 12.53(1) A ̊ ; b = 11.58(2) A ̊ ; c = 17.81(2) A ̊ ; β = 105.79°; space group, C2/ c. The structure was obtained using classical methods with R = 0.044 and R w = 0.056 for 2372 independent reflections. The most interesting result was the evidence for neptunyl dimers in the lattice, possibly as a result of cation-cation interactions. The two neptunium atoms in such dimers are 3.4824(8) Å apart. The neptunyl dinier is associated with four mellitate ligands. The sodium ions and the water molecules serve as bridging species to increase the crystalline cohesion.
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