Abstract
The benzimidazole ring in the title compound, C16H17N3O2S, is almost planar, with the greatest deviation from the mean plane being 0.032 (1) Å. The fused-ring system makes dihedral angles of 19.91 (7) and 24.51 (8)° with the best plane through each of the thiazol-4-yl and 1,3-dioxolan-4-yl rings, respectively; the latter exhibits an envelope conformation with the methylene C atom being the flap. Finally, the thiazol-4-yl ring makes a dihedral angle of 33.85 (9)° with the 1,3-dioxolan-4-yl ring. In the crystal, molecules are connected by a pair of C—H⋯π(imidazole) interactions to form centrosymmetric aggregates.
Highlights
The benzimidazole ring in the title compound, C16H17N3O2S, is almost planar, with the greatest deviation from the mean plane being 0.032 (1) A
Molecules are connected by a pair of C— HÁ Á Á(imidazole) interactions to form centrosymmetric aggregates
Cg1 is the centroid of the N2/N3/C4/C5/C10 ring
Summary
The benzimidazole ring in the title compound, C16H17N3O2S, is almost planar, with the greatest deviation from the mean plane being 0.032 (1) A. The fused-ring system makes dihedral angles of 19.91 (7) and 24.51 (8) with the best plane through each of the thiazol-4-yl and 1,3-dioxolan-4-yl rings, respectively; the latter exhibits an envelope conformation with the methylene C atom being the flap. The thiazol-4-yl ring makes a dihedral angle of 33.85 (9) with the 1,3-dioxolan-4-yl ring. Molecules are connected by a pair of C— HÁ Á Á(imidazole) interactions to form centrosymmetric aggregates
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More From: Acta crystallographica. Section E, Crystallographic communications
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