Abstract
The crystal structure of tetrakis(N,N′-diallylthiourea)nickel(II) iodide [Ni(C7H12N2S)4I2] has been determined by a three-dimensional X-ray analysis. FinalR, after anisotropic least-squares refinement, is 8·8%. The crystals are tetragonal (P4/n):a = 11·24(1),c = 15·43(1) A,Z = 2. Ni(II) is on a 4-fold axis; the coordination around it is flattened pyramidal and involves four sulphur atoms from four diallylthiourea molecules (Ni-S = 2·221 A). Ni(II) is out of the plane through the sulphur atoms by 0·40 A. Two I- ions lie on opposite sides with respect to the nickel atom along the 4-fold axis, at distances Ni...I(1) = 3·74 A, Ni...I(2) = 6·64 A. The orientation of the allylthiourea molecules is determined mainly by a hydrogen bond formed by one nitrogen (N(1)) with the iodine which is nearer to the nickel.
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