Abstract
The crystal and molecular structure of bis(N,N-diethyldithiocarbamato)palladium(II), Pd(S2CN(C2H5)2)2, has been determined by a three-dimensional X-ray analysis. The compound crystallizes in the tetragonal space groupP42/n with unit cell dimensionsa = 16·439(8) A andc = 6·247(3) A. The crystals are isomorphous with bis(N,N-diethyldithiocarbamato)platinum(II). Intensities were obtained with an automatic diffractometer. The structural parameters were refined by least-squares methods to a conventionalR factor of 0·038 for 600 non-zero observed reflections. The palladium is in planar coordination with four sulphur atoms, the two non-equivalent Pd-S bond lengths being 2·317(3) and 2·315(3) A.
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