Abstract
The dissociation energy of the van der Waals molecule Ca...HCl in its ground state, D00(Ca...HCl), has been determined using energy balance arguments. By combining collisional information from the Ca(3P)+HCl→CaCl(A 2Π)+H reaction with spectroscopic information from the Ca...HCl+hν→CaCl(A 2Π)+H reaction we found D00(Ca...HCl)≤150 meV.
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