Abstract
The aim of the study. To evaluate the dental status of children with different degrees of caries activity who constantly live in conditions of biogeochemical deficiency of fluorine and iodine and to determine the correlation dependence of indicators. Materials and methods. An examination of 251 children aged 5 to 11 years (129 girls – 51.4% and 122 boys – 48.6%), residents of the mountain and lowland zones of Zakarpattia region, was conducted. The level of hygiene was assessed with the help of the Fedorov–Volodkina hygienic index, and the caries resistance of tooth enamel was determined using the DIAGNOdent pen (KaVo, Germany) and TEP-test (V.P. Okushko, L.I. Kosareva, 1983). Mathematical analysis and verification of the accuracy of the results and the calculation of possible error values were carried out using the Statistica software and Microsoft Office Excel 2007. The statistical analysis of the received data was carried out using the Statistica 6.0 standard statistical software. Results. In the studied regions, the decompensated degree of caries activity in children aged 5 to 11 years prevailed. In the group with a compensated degree of caries activity, the hygiene index was 2.2 ± 0.02 points and 2.0 ± 0.07 points (р < 0.05), with a subcompensated degree of caries activity – 2.7 ± 0.02 points, 2.6 ± 0.6 points; (р < 0.05), with decompensated degree of caries activity – 3.07 ± 0.02 points with temporary and 3.15 ± 0.6 points with variable bite. A significant decrease in caries resistance of enamel is observed among schoolers of Rakhiv school №1, in particular among children with a decompensated degree of caries activity, where this indicator is equal to 82.3%, which is significantly more than the result obtained among children in Uzhhorod school No. 20 (68.2% ). Conclusions. It was statistically established that the presence of a decompensated degree of caries activity had a direct correlation with high rates of tooth enamel demineralization in all studied patients of both educational institutions (r = 0.87, p = 0.05).
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