Abstract

Let $$\alpha \ge 0$$ and $$k \ge 2$$ be integers. For a graph G, the total k-excess of G is defined as $$\text{ te }(G;k)=\sum _{v \in V(G)}\max \{d_G(v)-k,0\}$$ . In this paper, we propose a new closure concept for a spanning tree with bounded total k-excess. We prove that: Let G be a connected graph, and let u and v be two non-adjacent vertices of G. If G satisfies one of the following conditions, then G has a spanning tree T such that $$\text{ te }(T;k) \le \alpha$$ if and only if $$G+uv$$ has a spanning tree $$T'$$ such that $$\text{ te }(T';k) \le \alpha$$ : We also show examples to show that these conditions are sharp.

Full Text
Published version (Free)

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call