Abstract
In the compounds MgCu 2O 3 and CaCu 2O 3 the Cu and O atoms are connected topologically in the same way as in the fascinating spin-ladder compound SrCu 2O 3. In contrast to the latter, the Cu—O—Cu bonding angle corresponding to the “rungs” is significantly less than 180° in MgCu 2O 3 and CaCu 2O 3. As a consequence, the magnetic susceptibility is quite different compared with that of SrCu 2O 3. Single-phase samples of CaCu 2O 3 revealed a deficiency of Ca, a balancing excess in Cu, and an oxygen deficiency corresponding to Ca 1−xCu 2+xO 3−δ. The excess Cu atoms, which are located near the Ca sites, are in the 3d 10 state. The deficiency of oxygen causes a Curie term in the magnetic susceptibility due to the interruption of Cu—O—Cu bonds. From the overall behavior of the susceptibility an antiferromagnetic ordering at a Néel temperature of about 27 K is concluded.
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