Abstract

For the integral \[\int_\alpha ^\infty {e^{ - z(t - a )} I^{\lambda - 1} f(t)dt} \] an asymptotic expansion is obtained as $z \to \infty $. Here $\lambda $ is fixed, $0 < \lambda < 1, $, $I^{\lambda - 1} $ is the operator of fractional integration, and the expansion holds uniformly for $a \geqq 0$. A similar expansion is obtained for the integral from 0 to a and is applied to the solution of an integral equation.

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.