Abstract
An explanation is offered for the large difference in $B(E1)$ values of mirror transitions from ${\mathrm{\textonehalf{}}}^{+}$ state to the ground state, based on the difference in binding energy of the ${\mathrm{\textonehalf{}}}^{+}$ states. The binding energy determines the degree of coupling of the positive parity nucleon to the deformed $^{12}\mathrm{C}$ core, which in turn affects the $B(E1)$ value. The experimental asymmetry can be satisfied with a small change of the wave function.
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