Abstract
The turbulent potential model is a Reynolds‐averaged (RANS) turbulence model that is theoretically capable of capturing nonequilibrium turbulent flows at a computational cost and complexity comparable to two‐equation models. The ability of the turbulent potential model to predict nonequilibrium turbulent flows accurately is evaluated in this work. The flow in a spanwise‐driven channel flow and over a swept bump are used to evaluate the turbulent potential model′s ability to predict complex three‐dimensional boundary layers. Results of turbulent vortex shedding behind a triangular and a square cylinder are also presented in order to evaluate the model′s ability to predict unsteady flows. Early indications suggest that models of this type may be capable of significantly enhancing current numerical predictions of turbomachinery components at little extra computational cost or additional code complexity.
Highlights
The turbulent potential model is a Reynolds-averaged (RANS) turbulence model that is theoretically capable of capturing nonequilibrium turbulent flows at a computational cost and complexity comparable to two-equation models
For the unsteady vortex shedding behind a bluff body, Franke and Rodi (1991) compared the ability of different models to predict turbulent vortex shedding from a rectangular cylinder
The model does not hypothesize an explicit relationship between the turbulence and the mean flow and it is the least expensive RANS model that is theoretically capable of capturing nonequilibrium turbulent flows
Summary
The turbulent potential model is a Reynolds-averaged (RANS) turbulence model that is theoretically capable of capturing nonequilibrium turbulent flows at a computational cost and complexity comparable to two-equation models. For the unsteady vortex shedding behind a bluff body, Franke and Rodi (1991) compared the ability of different models to predict turbulent vortex shedding from a rectangular cylinder. Their conclusion is that some κ-ε models do not predict the right shedding frequency, but more expensive Reynolds stress transport models can produce results that are in good agreement with the experiments.
Sign-in/Register to view highlights & summary Talk to us
Join us for a 30 min session where you can share your feedback and ask us any queries you have
Schedule a callDisclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.
