Abstract
AbstractThe crystal structure of IF6[Ag(SbF6)3] has been determined by X‐ray single crystal and X‐ray powder diffraction analysis. The structure consists from [Ag(SbF6)3]– chains and [IF6]+ cations placed between them. Ag2+ is found in regular octahedral coordination of six fluorine atoms [Ag–F = 6 × 2.170(12) Å]. EXAFS analysis of Jahn–Teller distortions in IF6[Ag(SbF6)3] shows that Ag2+ surrounding is elongated octahedral at room temperature. EXAFS signals are fitted with four short and two long Ag–F distances [4 × 2.11(1) Å; 2 × 2.40(2) Å]. This result is in apparent contradiction with X‐ray diffraction studies where the [AgF6] moiety appears to be a regular octahedra. The Raman spectrum of IF6[Ag(SbF6)3] is in agreement with the presence of regular IF6 and deformed SbF6 groups.
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