Abstract
An analogue transformation is proposed for solving the axially symmetrical equation ∂2ψ/∂R2 - (1/R)∂ψ/∂R + ∂2ψ/∂z2 = 0 This consists of transforming the boundaries and coordinates by the rule R' = kR2, z' = z and then solving the transformation using the normal resistive paper technique. A first order mathematical justification of the method is given and a comparison is made between the solutions obtained in certain cases and those derived by numerical relaxation methods. Agreement between these solutions is very satisfactory.
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