Abstract

A novel technique using a set of artificial neural networks to identify and split merged measurements created by multiple charged particles in the ATLAS pixel detector is presented. Such merged measurements are a common feature of boosted physics objects such as tau leptons or strongly energetic jets where particles are highly collimated. The neural networks are trained using Monte Carlo samples produced with a detailed detector simulation. The performance of the splitting technique is quantified using LHC data collected by the ATLAS detector and Monte Carlo simulation. The number of shared hits per track is significantly reduced, particularly in boosted systems, which increases the reconstruction efficiency and quality. The improved position and error estimates of the measurements lead to a sizable improvement of the track and vertex resolution.

Highlights

  • The ATLAS Pixel Detector The silicon pixel detector [2] is the innermost layer of the tracking detector and provides precision measurements of the positions of charged particles

  • It is crucial for the reconstruction of primary vertices which give an estimate of the number of proton-proton interactions per bunch crossing, and for the identification of long-lived particles via the reconstruction of secondary vertices

  • The standard clustering provides excellent resolution for most clusters, it is inadequate for dense environments with multiple charged particles where charge is deposited in neighbouring pixels and clusters are shared between particles, as is illustrated in figure 1 (b)

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Summary

Introduction

2. The ATLAS Pixel Detector The silicon pixel detector [2] is the innermost layer of the tracking detector and provides precision measurements of the positions of charged particles. 3. Pixel Clustering Particles traversing the detector typically deposit charge in more than one pixel. The position of the particle at the point where it crosses the detector layer is computed from the signal heights inside the cluster of pixels: 1 x cs = x centre + ∆ x · Ω x − 2

Results
Conclusion
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