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Abstract
It is shown that with alumina both F − exchange and reaction with MoO 2(acac) 2 (acac = acetylacetonate) occur selectively with one type of hydroxyl group only: the one corresponding to the high-frequency (3775 cm −1) band in the IR spectrum of the alumina. In view of the chemistry involved—F −: anion exchange; MoO 2(acac) 2: very rapid reaction with OH −, no reaction with H +—this band must be due to the basic hydroxyl groups. It is established that the number of these groups can be determined via the reaction with MoO 2(acac) 2. VO(acac) 2 behaves in very much the same way toward alumina as MoO 2(acac) 2.
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