Abstract
AbstractThe hydrochlorides of the title compounds are obtained in moderate yields by refluxing 2‐chloro‐3‐aminopyridine or 3‐amino‐4‐chloropyridine, respectively, with an alkyl. Aralkyl‐, or aryl isothiocyanate in absolute ethanol solution. A proof is presented that the 2‐aminothiazolopyridine hydrochloride and not the isomeric o‐chloropyridylthiourea is the product of this reaction. The free‐bases may be obtained from the hydrochlorides with aqueous sodium bicarbonate. A mechanism for the formation of the thiazole ring is briefly considered. The interactions of 2‐chloro‐3‐aminopyridine with l‐substituted‐5‐mereapto‐1H‐tetrazoles are also described.
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