Abstract

An asymmetric ligand, (4‐py)–CH=N–C10H6–NH2 (L1), was prepared from 4‐pyridinecarboxaldehyde and 1,5‐diaminonaphthalene. The ligand L1 reacted with Cd(NO3)2·4H2O in methanol to give a discrete molecular complex, [Cd(L1)2(NO3)2(CH3OH)] (1). In addition, a 1D cadmium coordination polymer possessing a methanol molecule, {[Cd(L2)(CH3COO)2]·(CH3OH)}∞ (2), was prepared from a symmetric ligand (L2 = (3‐py)–CH=N–C10H6–N=CH–(3‐py)) and Cd(OAc)2·2H2O.

Full Text
Published version (Free)

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call