Abstract
Activating the non-symmetrical Bpin-Bdan diboron reagent with alkoxide leads to the formation of two possible adducts: MeO(-) →Bpin-Bdan or MeO(-) →Bdan-Bpin. Experimental and theoretical investigation confirms that the MeO(-) →Bpin interaction is preferred and thus selective formation of a C-Bdan bond upon reaction with an activated C=C bond.
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