Abstract

Let G be a group and ω(G) be the set of element orders of G. Let k∈ω(G) and sk be the number of elements of order k in G. Let nse(G)={sk∣k∈ω(G)}. In Khatami et al. and Liu’s works L3(2) and L3(4) are unique determined by nse(G). In this paper, we prove that if G is a group such that nse(G)=nse(U3(5)), then G≅U3(5).

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