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Abstract
In the title compound, C16H15NO, the two aromatic rings are approximately perpendicular; the carbonyl group is twisted out of the adjacent benzene ring by 14.8 (2)°. In the heterocyclic ring, the C atom linked to the carbonyl group and the C atom linked to the N atom have opposite deviations of 0.467 (5) and 0.184 (4) Å, respectively, from the plane of the benzene ring. The N atom lies approximately in the plane of the phenyl ring. There are no conventional hydrogen bonds; the packing of molecules in the crystal structure is stabilized by van der Waals forces.
Highlights
In the title compound, C16H15NO, the two aromatic rings are approximately perpendicular; the carbonyl group is twisted out of the adjacent benzene ring by 14.8 (2)
The C atom linked to the carbonyl group and the C atom linked to the N atom have opposite deviations of 0.467 (5) and 0.184 (4) A, respectively, from the plane of the benzene ring
R-factors based on F2 are statistically about twice as large as those based on F, and R- factors based on ALL data will be even larger
Summary
Key indicators: single-crystal X-ray study; T = 293 K; mean (C–C) = 0.005 A; R factor = 0.068; wR factor = 0.182; data-to-parameter ratio = 13.7. C16H15NO, the two aromatic rings are approximately perpendicular; the carbonyl group is twisted out of the adjacent benzene ring by 14.8 (2). The C atom linked to the carbonyl group and the C atom linked to the N atom have opposite deviations of 0.467 (5) and 0.184 (4) A , respectively, from the plane of the benzene ring. The N atom lies approximately in the plane of the phenyl ring. There are no conventional hydrogen bonds; the packing of molecules in the crystal structure is stabilized by van der Waals forces. Related literature For related literature, see: Johnson et al (1949); Anilkumar et al (2005); Kazak et al (2002)
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