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Abstract
In order to determine the position of CH2Cl group in the chloromethyl compound (I), 8-methylacacetin-7-methyl ether (II), m.p. 226°, was prepared and this was found to be identical with the reduction product, m.p. 226°, of (I). This has shown that the position of the CH2Cl group in this compound (I) is at 8. (II) was obtained from 3-methyl-2-hydroxy-4, 6-dimethoxyacetophenone anisoate which was derived to a diketone compound with sodium amide, cyclized with sulfuric acid to 8-methylacacetin-5, 7-dimethyl ether, and finaly demethylated with aluminum chloride.
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