Abstract

The room temperature reaction of dimethylplatinum (II)COD [COD = 1,5-cyclooctadiene] with a molar excess perfluoro- n-propyl iodide produces [Pt(C 3F 7) 2(COD)]. Perfluoro- iso-propyl iodide and perfluoro- n-butyl iodide gives the monosubstitute [Pt( i-C 3F 7)(CH 3)(COD)] and [Pt(C 4F 9)(CH 3)(COD)], respectively, consistent with steric hinderance suppressing the second substitution reaction. The crystal structure of [Pt(C 3F 7) 2(COD)] reveals square planar geometry about the platinum.

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