Abstract
Abstract It is investigated why the root-mean-square radius of the point neutron distribution is smaller by about 0.1 fm in non-relativistic mean-field models than in relativistic ones. The difference is shown to stem from the different values of the product of the effective mass and the strength of the one-body potential in the two frameworks. The values of those quantities are constrained by the Hugenholtz–Van Hove theorem. The neutron skin is not a simple function of the symmetry potential, but depends on the nucleon effective mass.
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