Abstract

In this work, we explore soft leptogenesis in the NMSSM framework extended by a right-handed neutrino superfield. We calculate the CP asymmetry, ε, and find it to be non-zero at tree-level without using thermal effects for the final state particles. This is in contrast to soft leptogenesis in the MSSM extended by a right-handed neutrino superfield where thermal effects are essential. The difference arises due to the presence of a 3-body decay of the sneutrino in the NMSSM that violates lepton number at tree-level. Apart from this, we also find that ε ≠ 0 if the additional singlet scalar has a complex vacuum expectation value while all the other NMSSM parameters including the soft SUSY breaking ones relevant for CP asymmetry remain real. We estimate the order of magnitudes of these parameters to produce sufficient baryon asymmetry of the Universe.

Highlights

  • Thermal masses for the final products are considered

  • In this work, we explore soft leptogenesis in the next-to-minimal supersymmetric standard model (NMSSM) framework extended by a right-handed neutrino superfield

  • By using the NMSSM extended by the RH neutrino superfield, we present a soft leptogenesis scenario that creates a lepton asymmetry at the tree-level decay of the RH sneutrino without using thermal mass factors

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Summary

Terms relevant for soft leptogenesis

The terms from the superpotential required for leptogenesis via sneutrino decay are:. We consider λN , κ to be all real and positive. We remove the i, j indices from the leptons and the u index from the Higgs superfield for brevity. The fermionic part of the Lagrangian is given by: Lf = YN LH N + λN SN N + YN LHN. The soft SUSY-breaking Lagrangian terms that play a role in leptogenesis are:. The superpotential and the soft breaking terms combine to give the following interactions for Nand σ which could in principle contribute to soft leptogenesis due to mixing between the particle and anti-particle states through the soft terms: Lint = N YN H L + 2λN YN∗ vSeiδH∗L∗ + 2λN YN∗ σH∗L∗ + AN YN HL + σ λN N N + AλλN N N + h.c.,.

CP asymmetry
Ndecays
General constraints
A simpler form for ε
Results and discussions
Case 1: δ is near zero
Conclusion

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