Abstract
Soluble luminescent complexes of divalent lanthanides, LnCl2·xTHF (Ln = Eu, Yb, and Sm), were obtained for the first time by reduction of LnIII to LnII in reactions of the lanthanide trichloride hexahydrates LnCl3·6H2O with Bui 2AlH in THF. The photoluminescence spectra and other spectral characteristics of LnCl2·xTHF were examined.
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