Abstract

The reactions of PtRu 5(CO) 16(μ 6-C) ( 1) with Ph 3GeH and Ph 3SnH afforded the trimetallic cluster complexes PtRu 5(CO) 15(μ-GePh 2)(μ 6-C) ( 4) and PtRu 5(CO) 15(μ-SnPh 2)(μ 6-C) ( 5), respectively, in good yields. Both the compounds consist of an octahedral cluster of one platinum and five ruthenium atoms with an interstitial carbido ligand in the center. The bridging CO ligand in 1 was replaced by a bridging GePh 2 group in 4 and a bridging SnPh 2 group in 5. The lead homologue PtRu 5(CO) 15(μ-PbPh 2)(μ 6-C) ( 6) was obtained from the reaction of 1 with Pb 2Ph 6. The reaction of PtRu 5(CO) 15(PMe 2Ph)(μ 6-C) ( 2) with Ph 3SnH yielded the phosphine derivative of 5, PtRu 5(CO) 14(μ-SnPh 2)(PMe 2Ph)(μ 6-C) ( 7). Compound 7 was obtained in a higher yield from the reaction of 5 with PMe 2Ph. The reaction of Ru 6(CO) 14(η 6-C 6H 6)(μ 6-C) ( 3) with Ph 3SnH yielded the new hexaruthenium complex Ru 6(CO) 13(μ-SnPh 2)(η 6-C 6H 6)(μ 6-C) ( 8) containing a bridging SnPh 2 ligand. Evidence for benzene formation in the formation of compound 5 indicates the fate of the phenyl group that was cleaved from the tin atom in that reaction.

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