Abstract
The magnetic Compton profile of $\mathrm{Ca}{\mathrm{Ru}}_{0.85}{\mathrm{Fe}}_{0.15}{\mathrm{O}}_{3}$ has been measured to elucidate the spin moment structure. The obtained profile is decomposed into two partial profiles of Ru $4d$ and Fe $3d$, calculated on the basis of a Hartree-Fock molecular orbital calculation. This decomposition reveals that a spin moment of $0.38\phantom{\rule{0.3em}{0ex}}{\ensuremath{\mu}}_{B}$ per formula unit is induced on Ru and the moment aligns antiparallel to the spin moment ($\ensuremath{-}0.18\phantom{\rule{0.3em}{0ex}}{\ensuremath{\mu}}_{B}$ per formula unit) of Fe. The observed antiferromagnetic spin coupling can be explained by the superexchange interaction between Ru and Fe ions via an O ion.
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