Abstract
AbstractBenzylation of 6‐methylthiopurine (I) and its N‐alkyl derivatives in an aprotic solvent usually leads to a single reaction product. Both (I) and its 7‐benzyl derivative are attacked at N‐3, in analogy to the behavior of the corresponding 7‐methylpurine. Reaction of the 9‐benzyl derivative of (I), followed by thiohydrolysis of the thioether group, gives 7, 9‐dibenzyl‐6‐thiopurine betaine. This result is in disagreement with an earlier report that the 9‐methyl derivative is substituted by methyl iodide at N‐3. Re‐investigation shows, however, that in this case too, the 9‐alkyl group directs further attack toward N‐7. Methylation and benzylation of (I) thus obey the same general rules.
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