Abstract
Substitute (2) and (11) into (1) to find equation (8). Table 1 below gives the probability for the circular case for d = 1(1)30, N = 2(1)35. For example, in problem (a), d 2, N = 18, D = 365; from Table 1, the probabili-ty -that there are at least two girls with the same or adjacent birthdays is 0.730. To evaluate probabilities no-t included in Table 1, use tables of logarithms of fac-torials as illustrated in Mosteller [3, p. 47]; for certaini problems one might use approxiimations similar to those in Feller [1, p. 32]. For example, equation (7) gives the solutioin to problem (b), (N = 18, D = 365),
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