Abstract
This article considers a classical solution of the boundary problem for the four-order strictly hyperbolic equation with four different characteristics. Note that the well-posed statement of mixed problems for hyperbolic equations not only depends on the number of characteristics, but also on their location. The operator appearing in the equation involves a composition of first-order differential operators. The equation is defined in the half-strip of two independent variables. There are Cauchy’s conditions at the domain bottom and periodic conditions at other boundaries. Using the method of characteristics, the analytic solution of the considered problem is obtained. The uniqueness of the solution is proved. We have also noted that the solution in the whole given domain is a composition of the solutions obtained in some subdomains. Thus, for the obtained classical solution to possess required smoothness, the values of these piecewise solutions, as well as their derivatives up to the fourth order must coincide at the boundary of these subdomains. A classical solution is understood as a function that is defined everywhere at all closure points of a given domain and has all classical derivatives entering the equation and the conditions of the problem.
Highlights
This article considers a classical solution of the boundary problem for the four-order strictly hyperbolic equation with four different characteristics
Note that the well-posed statement of mixed problems for hyperbolic equations depends on the number of characteristics, and on their location
The equation is defined in the half-strip of two independent variables
Summary
This article considers a classical solution of the boundary problem for the four-order strictly hyperbolic equation with four different characteristics. 136 Proceedings of the National academy of sciences of Belarus, рhysics and mathematics series, 2018, vol 54, no. ( ) где g j j = 1, 4 – произвольные функции с областиями определения D ( g1 ), D ( g3 )= ((−∞,l]), D ( g2 ), D ( g= 4 ) ([0, +∞)), если (t, x)∈Q,и vp – частное решение уравнения (1).
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