Abstract
In the title compound, C13H10BrNO, the benzene ring planes are inclined at an angle of 48.85 (17)°, resulting in a nonplanar molecule. A characteristic of aromatic Schiff bases with N-aryl substituents is that the terminal phenyl rings are twisted relative to the HC=N plane. In this case, the HC=N unit makes dihedral angles of 11.1 (4) and 38.5 (3)° with the hydroxybenzene and bromobenzene rings, respectively. In the crystal, the molecules are linked by O—H⋯N hydrogen bonds to form infinite (C8) chains along the b axis.
Highlights
C13H10BrNO, the benzene ring planes are inclined at an angle of 48.85 (17), resulting in a nonplanar molecule
A characteristic of aromatic Schiff bases with N-aryl substituents is that the terminal phenyl rings are twisted relative to the HC N plane
The molecules are linked by O—H N hydrogen bonds to form infinite (C8) chains along the b axis
Summary
C13H10BrNO, the benzene ring planes are inclined at an angle of 48.85 (17) , resulting in a nonplanar molecule. A characteristic of aromatic Schiff bases with N-aryl substituents is that the terminal phenyl rings are twisted relative to the HC N plane. In this case, the HC N unit makes dihedral angles of 11.1 (4) and 38.5 (3) with the hydroxybenzene and bromobenzene rings, respectively. The molecules are linked by O—H N hydrogen bonds to form infinite (C8) chains along the b axis
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More From: Acta Crystallographica Section E Structure Reports Online
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